3y^2+28y-20=

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Solution for 3y^2+28y-20= equation:


Simplifying
3y2 + 28y + -20 = 0

Reorder the terms:
-20 + 28y + 3y2 = 0

Solving
-20 + 28y + 3y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-10 + -1y)(2 + -3y) = 0

Subproblem 1

Set the factor '(-10 + -1y)' equal to zero and attempt to solve: Simplifying -10 + -1y = 0 Solving -10 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1y = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1y = 0 + 10 -1y = 0 + 10 Combine like terms: 0 + 10 = 10 -1y = 10 Divide each side by '-1'. y = -10 Simplifying y = -10

Subproblem 2

Set the factor '(2 + -3y)' equal to zero and attempt to solve: Simplifying 2 + -3y = 0 Solving 2 + -3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -3y = 0 + -2 -3y = 0 + -2 Combine like terms: 0 + -2 = -2 -3y = -2 Divide each side by '-3'. y = 0.6666666667 Simplifying y = 0.6666666667

Solution

y = {-10, 0.6666666667}

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